24=3x^2-6x

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Solution for 24=3x^2-6x equation:



24=3x^2-6x
We move all terms to the left:
24-(3x^2-6x)=0
We get rid of parentheses
-3x^2+6x+24=0
a = -3; b = 6; c = +24;
Δ = b2-4ac
Δ = 62-4·(-3)·24
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*-3}=\frac{-24}{-6} =+4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*-3}=\frac{12}{-6} =-2 $

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